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Information for RPM python-pycurl-7.43.0.6-8.el9.src.rpm

ID270625
Namepython-pycurl
Version7.43.0.6
Release8.el9
Epoch
Archsrc
SummaryA Python interface to libcurl
DescriptionPycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features.
Build Time2022-07-04 14:41:52 GMT
Size229.83 KB
722b368df02488280f6478f50e3e389a
LicenseLGPLv2+ or MIT
Buildrootdist-circle9-build-76331-24611
Provides
python-pycurl-debuginfo = 7.43.0.6-8.el9
python-pycurl-debugsource = 7.43.0.6-8.el9
python3-pycurl = 7.43.0.6-8.el9
Obsoletes No Obsoletes
Conflicts No Conflicts
Requires
gcc
libcurl-devel
make
openssl-devel
python3-devel
python3-setuptools
rpmlib(CompressedFileNames) <= 3.0.4-1
rpmlib(FileDigests) <= 4.6.0-1
vsftpd
Recommends No Recommends
Suggests No Suggests
Supplements No Supplements
Enhances No Enhances
Files
1 through 4 of 4
Name ascending sort Size
0001-python-pycurl-7.43.0.6-python-3.10.patch1.96 KB
0002-python-pycurl-7.43.0-tls-backend.patch3.67 KB
pycurl-7.43.0.6.tar.gz212.75 KB
python-pycurl.spec17.42 KB
Component of No Buildroots